Collections of LGO Question papers with Answers

Solved Questions - LGO Exam held on dated 15.09.2013

1 Rs 675 amount to Rs 837 in four years at simple interest . If the interest rate is decreased by 2 % then amount will be 

A 729 b 753 c 763 d 783 

S I for four years 837-675= 162

Actual interest rate is 6 % if 2 % is decreased ie 4 % ,, Then amount is 783/-

Answer d 783

2 What least number which must be added to 1056 so that the sum is completely divisible by 23?

A 3 b 18 c 2 d 21

23) 1056 (45
92
--
136
115
--
21
--
Required number = (23 - 21) = 2. Answer c 2 

3 In a school with 600 students , the average age of the boys is 12 years and that of Girls is 11 years . if the average age of the school is 11 years and 9 months then the number of girls in the school is 

A 450 b 250 c 150 d 350

Let the number of Girls be X , Then number of boys = (600-x)
(11 4/3 * 600 ) = 11 x 12 (600-x)
X=7200-7050 =150 Answer c 150 

4 Ram bought a cycle and sold it for Rs 4550 which is 30 % more than this original price . What is the original price of the cycle 

A 3500/- b 3800/- c 3600/- d 3400/-

Let cost price (C.P.) = 100. Profit = 30 %. Selling price (S.P.) = (100 + 30) = 130.
If selling price (S.P.) is 130, then cost price (C.P.) is 100.
If selling price (S.P.) is 1, then cost price (C.P.) is $ (100/130).
If selling price (S.P.) is 4550, then cost price (C.P.) is (100 /130 × 4550)= 3500 Answer A 3500/- 

5 Rahim sales a cow at a loss of 15 % . if he has sold it for Rs 150 more than he would have made a profit of 10 % . Cost price of the cow was

A 660 b 600 c 575 d None of these 

Let cost price be P, Sold price =85 % of P, 85/100*P+150=110/100*P
25/100*P =150 25P=15000 P=15000/25= 600 Anser 600

6 There are some parrots and some tigers in a forest . if the total number of animal heads in the forest are 858 and total number of animal legs are 1746. . What is the number of parrots in the forest

A 843 b 847 c 800 d None of these 

Let the no of parrots is assumed as X
Total number of animals = 858
Total tigers = 858-x Total legs = 2x=4(858-x)=1746
=2x+3432-4x=1746 2x=3432-1746=1686 X=1686/2=843 Answer a 843 

 7 LCM of 36 , 45,52, 108 and 236 is a
A 414180 b 480414 c 441180 d none of these

36 = 2*2*3*3* 45 = 3*3*5 52 = 2*2*13 108 = 2*2*3*3*3* 236 = 2*2*59
Therefore, L.C.M of 36, 45, 52, 108, 236 = 2*2*3*3*3*5*13*59 = 414180 Answer a 414180

8 Salaries of Akash , Babloo and chintu are in the ratio of 2:3:5 . If their salaries were increased by 15 % , 10 % and 20 % respectively What will be the new ratio of their salaries ?

A 3:3:10 B 23:33:60 C 20:22:40 D None of these 

Let Akash = 2 Babloo = 3 and Chintu = 5
Then 100/115=2 = 23/10
100/110=3 = 33/10
120/100=5= 6
Then new ratio is 23/10 :33/10: 6 = 23:33:60 Answer b 23:33:60 

9 A man earns Rs 20 on the first day and spends Rs 15 on the next day . He again earns rs 20 on the third day and spends rs 15 on the fourth day . if he continues to save like how soon will have Rs 60 in hand 

A on 30 the day b On 40th Day c On 27th Day D On 17th day E

Explanation: Money earned in 2 days = Rs.(20 - 15) = Rs. 15.
Money earned in 16 days = Rs.(5/2 x 16) ‹=›Rs. 40.
On 17th day, money in hand = Rs.(40 + 20 ) = Rs. 60. Answer d 17th Day 

10 Ajay can do a piece of work in 25 days and Sanjay can finish it in 20 days . They work together for 5 days and Ajay goes away . how many days will Sanjay finish the remaining work

A 11 days b 12 days c 14 days d None of these

1 days work of Ajay =1/25
Sanjay = 1/20
So (Ajay+Sanjay)= 1/25+1/20=9/100
5 days work of Ajaya and Sajay=45/100
Remaining work = 1-45/100=55/100
Sajay can do 55/100 work in 55/100/1/20 = 11 Days
Answer a 11 Days 

11 The decimal representation of a rational number is 

A Always terminating b Either terminating or repeating c Either terminating or non repeating

Answer b 

12 A hemispherical bowl of internal radius 9 cm contains a liquid , The liquid is to be filled into cylindrical shaped small bottles of diameter 3 cm and height 4 cm . How many bottles will be needed to empty the bowl

A 45 b 54 c 35 d 48

Radius of hemisphere= 9 cm
volume of hemisphere= 2/3 π r3
= 2/3 x9x9x9 π = 486 π
radius of cylindrical shaped bottles= 3/2 cm
height= 4 cm, volume of bottles= π r2h
= 3/2x 3/2 x 4 π =9 π now,
Reaquired no. of bottles= volume of hemisphere/ volume of bottles
. =486 π/9π . =54
Hence, no. of bottles required to empty the bowl = 54 Answer b 54 

13 If the numerator of a fraction is increased by 200 % and the denominator is increased by 300 % the resultant fraction is 6/11 . What was the original fraction . 

A 5/11 b 7/11 . c 8/13 d 8/11 

If numerator increase 200 % then Numerator will be x+2x =3x and denominator increased by 300% means denominator will be y = 3y =4y new fraction will be 3x/4y =6/66 (g
3x/4y = 6/11
dividing numerator by 3 and denominator by 4 both side we will get
x/y =6/3/11/4
x/y=6x4/11x3
x/y =24/33
x/y =8/11 Answer d 8/11 

14 If the ratio of areas of two squares is 9:1 the ratio of perimeter is 

A 3:1 b 1:2 c 3:2 d None of these 

15 40 Laourers can handle a task of debri clearance in 7 days .if 5 % of the labourers leave after 2 days . What is the total number of days the task will take 

A 5 5/19 b 5 ½ c 5 7/8 d 5 8/19 

16 If eggs are bought at 10 for Rs 8 and sold at 4 for Rs 5 the business result in 

A 50 % loss b 56 1/3 % gain c 51 % gain d 56 ¼ % gain 

Answer 56 ¼ % gain 

17 A fruit seller buys lemons at 2 for a rupees. His gain percent is 

A 10 % b 15 % c 20 % d 25 % 

Answer 20 % 

18 A car is moving with a speed of 36 km/h . How much time in seconds it will take to cross a 500 m long bridge .

A 40 b 45 c 50 d 55

Speed 36 KM/H = 36*5/18 M/S =10 M/S
So time taken to cross 500m bridge = 500/10 = 50 Second
 Answer 50

19 . Two cars start from the same point at 8 am . In the same direction . The speed of the first car is 60 km/h and the speed of second car is 55 km/h . The distance between them at 2 p. m on the same day is 

A 20 km b 25 km c 28 km d 30 km 

Time duration 14-8 = 6 Hrs 2 PM ( 14 hrs)
distance by first car 6*60 360 KM
Distance by IInd car = 6*55 =330 KM
So distance between two car 30 KM Answer 30 KM 

20 The distance between two cities A and B is 520 km . One car starts from city A towards city B with the speed of 60 km/h. At the same time another car starts from city B towards city A with a speed of 70 km/h . After how many hours they will cross each other 

A 3 hours b 4 Hours d 5 hours d 6 hours

Let distance travelled by A= X
Distance travelled by B= (520-X)
X/60=520-x/70
70X=(520-X)60
70X=520*60-60X
130X=520*60 X=240 ie Time =240/60= 4 Hrs
Answer 4 Hrs

21 A car towards 50 km in first hour , 60 Km in second hour and 43 km in third hour . The average speed of the car is 

A 43 KM/h b 50 KM/h c 51 KM/h d 55 KM/h

153/3 Answer 51 KM/h 

22 A car travels a distance of 150 km in 3 hours and next 242 km in 4 hours . The average speed of car for complete journey

A 50 km/h b 55.25 km/h c 56 km/h d 58 km/h 

Answer 56 KM/ h 

23 If the diagonals of a rhombus are of measure 12 cm and 16 cm . then this measure of its side is 

A 10 cm b 20 cm c 15 cm d 96 cm 

12/2 cm = 6 cm and 16/2 cm = 8 cm long.
Answer a 10 cm 

24 A watch was sold at a profit of 15 % . If its cost had been 5 % less and it had been sold for Rs 21 less , then the profit would have been 10 % . Find the cost price of the watch 

A 200 b 400 c 190 d None of these 

Answer 200 

25 60 % of the students in a school are boys . if the number of girls in the school is 300. Then the number of boys is 

A 500 b 300 c 450 d 750

If 60% are boys, then 40% must make up the girls.
Let x = total number of students
then .40x = 300
x = 300/.40 = 7.5*100=750 750-300=450 Total no of boys 450 Answer c 450 

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